
Logarithm TheoremPythagorean TheoremCombinatoricsQuadratic EquationsSequence and SeriesLinear AlgebraDiophantine EquationElliptic Curve FactorMultiplication, DivisionIndicesHighest Common Factor, Lower Common MultipleEquationsQuadratic Equations
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AlgebraSimultaneous EquationsGeneral Solution with Two Unknown QuantitiesGiven๐1๐ฅ+๐1๐ฆ=๐1๐2๐ฅ+๐2๐ฆ=๐2 }, ๐ฅ= ๐1๐2โ๐2๐1๐1๐2โ๐2๐1๐ฆ= ๐1๐2โ๐2๐1๐1๐2โ๐2๐1 General Solution with Three Unknown QuantitiesGiven๐1๐ฅ+๐1๐ฆ+๐1๐ง=๐1๐2๐ฅ+๐2๐ฆ+๐2๐ง=๐2๐3๐ฅ+๐3๐ฆ+๐3๐ง=๐3 }, ๐ฅ= ๐1(๐2๐3โ๐3๐2)+๐2(๐3๐1โ๐1๐3)+๐3(๐1๐2โ๐2๐1)๐1(๐2๐3โ๐3๐2)+๐2(๐3๐1โ๐1๐3)+๐3(๐1๐2โ๐2๐1)and symmetrical forms for ๐ฆ and ๐ง. Methods of Solving simultaneous Equations between Two Unknown QuantitiesBy substitutionFind one unknown in terms of the other from one of the two equations, and substitute this value in the remaining equation. Then solve the resulting equation.Examples๐ฅ+๐ฆ=237๐ฆ=28 }From (2), ๐ฆ=4, substitute in (1); thus ๐ฅ+20=23, ๐ฅ=3 By the Method of MultipliersExamples3๐ฅ+5๐ฆ=362๐ฅโ3๐ฆ=5 }Eliminate ๐ฅ by multiplying (1) by 2 and (2) by 3; thus 6๐ฅ+10๐ฆ=726๐ฅโ9๐ฆ=15 }By subtraction 19๐ฆ=57 ๐ฆ=3 By substitution in (2) ๐ฅ=7 By changing the quantities sought๐ฅโ๐ฆ=2๐ฅ2โ๐ฆ2+๐ฅ+๐ฆ=30 }Let ๐ฅ+๐ฆ=๐ข, ๐ฅโ๐ฆ=๐ฃ, and substitute in equations: ๐ฃ=2๐ข๐ฃ+๐ข=30 }โด 2๐ข+๐ข=30 ๐ข=10 โด ๐ฅ+๐ฆ=10 ๐ฅโ๐ฆ=2 From which ๐ฅ=6, and ๐ฆ=4 Examples๐ฅ+๐ฆ๐ฅโ๐ฆ+10 ๐ฅโ๐ฆ๐ฅ+๐ฆ=9๐ฅ2+7๐ฆ2=64 }Substitute ๐ง for ๐ฅ+๐ฆ๐ฅโ๐ฆin (1): โด 2๐ง+ 10๐ง=9 2๐ง2โ9๐ง+10=0 From which ๐ง= 52or 2, ๐ฅ+๐ฆ๐ฅโ๐ฆ=2 or 52. From which ๐ฅ=3๐ฆ or 73๐ฆ Substitute in (2), thus ๐ฆ=2 and ๐ฅ=6, or ๐ฆ= 6and ๐ฅ=2 Examples}Divide each quantity by ๐ฅ๐ฆ 3๐ฆ+ 5๐ฅ=1 2๐ฆ+ 7๐ฅ=3 }Multiply (3) by 2, and (1) by 3, and by subtraction ๐ฆ is eliminated. By Substituting ๐ฆ=๐ก๐ฅBy Substituting ๐ฆ=๐ก๐ฅ, when the equations are homogeneous in the terms which contain ๐ฅ and ๐ฆ.Examples}From (1) and (2), }(3) gives 52+7๐ก=5๐ก2 A quadratic equation from which ๐ก must be found, and its value substituted in (4). ๐ฅ is thus determined; and then ๐ฆ from ๐ฆ=๐ก๐ฅ. Examples}From (1) and (2), by putting ๐ฆ=๐ก๐ฅ, }Squaring (4), ๐ฅ2(9๐ก2โ12๐ก+4)=16 โด 9๐ก2โ12๐ก+4=2+๐ก+3๐ก2, a quadratic equation for ๐ก. ๐ก being found from this, equation (4) will determine ๐ฅ; and finally ๐ฆ=๐ก๐ฅ. Sources and Referenceshttps://archive.org/details/synopsis-of-elementary-results-in-pure-and-applied-mathematics-pdfdriveยฉsideway ID: 210600003 Last Updated: 6/3/2021 Revision: 0 Ref: References
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