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`-=[]โŸจโŸฉ\;',./~!@#$%^&*()_+{}|:"<>? ๐‘Ž๐‘๐‘๐‘‘๐‘’๐‘“๐‘”โ„Ž๐‘–๐‘—๐‘˜๐‘™๐‘š๐‘›๐‘œ๐‘๐‘ž๐‘Ÿ๐‘ ๐‘ก๐‘ข๐‘ฃ๐‘ค๐‘ฅ๐‘ฆ๐‘ง ร…โ€‰โˆ’โ€‚ร—โ€ƒโ‹…โˆ“ยฑโˆ˜๊žŠ๏นฆโˆ—โˆ™ โ„ฏ ๐”ธ๐”นโ„‚๐”ป๐”ผ๐”ฝ๐”พโ„๐•€๐•๐•‚๐•ƒ๐•„โ„•๐•†โ„™โ„šโ„๐•Š๐•‹๐•Œ๐•๐•Ž๐•๐•โ„ค๐ด๐ต๐ถ๐ท๐ธ๐น๐บ๐ป๐ผ๐ฝ๐พ๐ฟ๐‘€๐‘๐‘‚๐‘ƒ๐‘„๐‘…๐‘†๐‘‡๐‘ˆ๐‘‰๐‘Š๐‘‹๐‘Œ๐‘ โˆผโˆฝโˆพโ‰โ‰‚โ‰ƒโ‰„โ‰…โ‰†โ‰‡โ‰ˆโ‰‰โ‰Œโ‰โ‰ โ‰ก โ‰คโ‰ฅโ‰ฆโ‰งโ‰จโ‰ฉโ‰ชโ‰ซ โˆˆโˆ‰โˆŠโˆ‹โˆŒโˆ โŠ‚โŠƒโŠ„โŠ…โІโЇ ๐›ผ๐›ฝ๐›พ๐›ฟ๐œ€๐œ๐œ‚๐œƒ๐œ„๐œ…๐œ†๐œ‡๐œˆ๐œ‰๐œŠ๐œ‹๐œŒ๐œŽ๐œ๐œ๐œ‘๐œ’๐œ“๐œ” โˆ€โˆ‚โˆƒโˆ…โฆฐโˆ†โˆ‡โˆŽโˆžโˆโˆดโˆต โˆโˆโˆ‘โ‹€โ‹โ‹‚โ‹ƒ โˆงโˆจโˆฉโˆช โˆซโˆฌโˆญโˆฎโˆฏโˆฐโˆฑโˆฒโˆณ โˆฅโ‹ฎโ‹ฏโ‹ฐโ‹ฑ โ€– โ€ฒ โ€ณ โ€ด โ„ โ— สน สบ โ€ต โ€ถ โ€ท ๏น ๏น‚ ๏นƒ ๏น„ ๏ธน ๏ธบ ๏ธป ๏ธผ ๏ธ— ๏ธ˜ ๏ธฟ ๏น€ ๏ธฝ ๏ธพ ๏น‡ ๏นˆ ๏ธท ๏ธธ โœ   โ   โŽด  โŽต  โž   โŸ   โ    โก โ†โ†‘โ†’โ†“โ†คโ†ฆโ†ฅโ†งโ†”โ†•โ†–โ†—โ†˜โ†™โ–ฒโ–ผโ—€โ–ถโ†บโ†ปโŸฒโŸณ โ†ผโ†ฝโ†พโ†ฟโ‡€โ‡โ‡‚โ‡ƒโ‡„โ‡…โ‡†โ‡‡ โ‡โ‡‘โ‡’โ‡“โ‡”โ‡Œโ‡โ‡โ‡•โ‡–โ‡—โ‡˜โ‡™โ‡™โ‡ณโฅขโฅฃโฅคโฅฅโฅฆโฅงโฅจโฅฉโฅชโฅซโฅฌโฅญโฅฎโฅฏ
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Content

Algebra
โ€ƒSurds
โ€ƒโ€ƒExamples
โ€ƒโ€ƒExamples
โ€ƒโ€ƒExamples
โ€ƒโ€ƒExamples
โ€ƒโ€ƒExamples
โ€ƒโ€ƒExamples
โ€ƒโ€ƒExamples
โ€ƒโ€ƒProperties
โ€ƒโ€ƒExamples
โ€ƒโ€ƒGeneral Formula
โ€ƒโ€ƒExamples
โ€ƒโ€ƒExamples
โ€ƒโ€ƒExamples
โ€ƒโ€ƒExamples
โ€ƒโ€ƒTheorems
โ€ƒโ€ƒExamples
โ€ƒSources and References

Algebra

Surds

Examples

To reduce 32808. Decompose the number into its prime factors, thus, 32808=323โ‹…33โ‹…13=6313

Examples

3๐‘Ž15๐‘10๐‘8=๐‘Ž153๐‘103๐‘83=๐‘Ž5๐‘93+13๐‘63+23=๐‘Ž5๐‘3๐‘13๐‘2๐‘23=๐‘Ž5๐‘3๐‘2โ‹…3๐‘๐‘2

Examples

To bring 543 to an entire surd. 543=4543=541875

Examples

๐‘ฅ23๐‘ฆ15๐‘ง12=๐‘ฅ2030๐‘ฆ630๐‘ง1530=30๐‘ฅ20๐‘ฆ6๐‘ง15

Examples

To rationalise fractions having surds in their demoninators. 17=77 137=34937โ‹…349=34937ร—49=3497 39โˆ’80=3(9+80)(9โˆ’80)(9+80)=3(9+80)81โˆ’80=3(9+80)

Examples

11+23โˆ’2=1+23+2(1+23โˆ’2)(1+23+2)=1+23+2(1+23)2โˆ’2=1+23+211+43  =(1+23+2)(11โˆ’43)(11+43)(11โˆ’43)=(1+23+2)(11โˆ’43)121โˆ’48  =(1+23+2)(11โˆ’43)73

Examples

133โˆ’2=1313โˆ’212 Put 313=๐‘ฅ, 212=๐‘ฆ, and take 6 the L.C.M. of the denominators 2 and 3, then 1๐‘ฅโˆ’๐‘ฆ=๐‘ฅ5+๐‘ฅ4๐‘ฆ+๐‘ฅ3๐‘ฆ2+๐‘ฅ2๐‘ฆ3+๐‘ฅ๐‘ฆ4+๐‘ฆ5๐‘ฅ6โˆ’๐‘ฆ6 therefore 1313โˆ’212=313โ‹…5+313โ‹…4212+313โ‹…3212โ‹…2+313โ‹…2212โ‹…3+313212โ‹…4+212โ‹…5313โ‹…6โˆ’212โ‹…6 133โˆ’2=339+33322+6+23922+433+429โˆ’8  =339+3672+6+26648+433+42 Similarly, 133+2 Here the result will be the same as in the last example if the signs of the even terms be changed.

Properties

A surd cannot be partly rational; that is, ๐‘Ž cannot be equal to ๐‘ยฑ๐‘. Proved by squaring. The product of two unlike squares is irrational; 7ร—3=21, an irrational quantity. The sum or difference of two unlike surds cannot produce a single surd; that is, ๐‘Ž+๐‘ cannot be equal to ๐‘. By squaring. If ๐‘Ž+๐‘š=๐‘+๐‘›; then ๐‘Ž=๐‘ and ๐‘š=๐‘›. Above Theorems are proved indirectly. if ๐‘Ž+๐‘=๐‘ฅ+๐‘ฆ then ๐‘Žโˆ’๐‘=๐‘ฅโˆ’๐‘ฆ by squaring and above theorem.

Examples

To express in two terms 7+26 Let 7+26=๐‘ฅ+๐‘ฆ then by squaring and about theorem ๐‘ฅ+๐‘ฆ=7 and by about theorem ๐‘ฅโˆ’๐‘ฆ=72โˆ’(2 6)2=49โˆ’24=5 โˆด ๐‘ฅ=6 and ๐‘ฆ=1 Result 6+1

General Formula

General formula for the same ๐‘Žยฑ๐‘=ยฝ(๐‘Ž+๐‘Ž2โˆ’๐‘)ยฑยฝ(๐‘Žโˆ’๐‘Ž2โˆ’๐‘) Observe that no simplification is effected unless ๐‘Ž2โˆ’๐‘ is a perfect square.

Examples

To simplify 3๐‘Ž+๐‘ Assume 3๐‘Ž+๐‘=๐‘ฅ+๐‘ฆ Let ๐‘=3๐‘Ž2โˆ’๐‘. Then ๐‘ฅ must be found by trial from the cubic equation 4๐‘ฅ3โˆ’3๐‘๐‘ฅ=๐‘Ž and ๐‘ฆ=๐‘ฅ2โˆ’๐‘ No simplification is effected unless ๐‘Ž2โˆ’๐‘ is a perfect cube.

Examples

37+52=๐‘ฅ+๐‘ฆ ๐‘=349โˆ’50=โˆ’1 4๐‘ฅ3+3๐‘ฅ=7; โˆด ๐‘ฅ=1, ๐‘ฆ=2 Result 1+2

Examples

393โˆ’113=๐‘ฅ+๐‘ฆ two different surds Cubing, 93โˆ’113=๐‘ฅ๐‘ฅ+3๐‘ฅ๐‘ฆ+3๐‘ฆ๐‘ฅ+๐‘ฆ๐‘ฆ; โˆด 93=(๐‘ฅ+3๐‘ฆ)๐‘ฅ112=(3๐‘ฅ+๐‘ฆ)๐‘ฆ}; โˆด ๐‘ฅ=3 and ๐‘ฆ=2

Examples

To simplify (12+43+45+215) Assume (12+43+45+215)=๐‘ฅ+๐‘ฆ+๐‘ง Square, and equate corresponding surds. Result 3+4+5

Theorems

To express ๐‘›๐ดยฑ๐ต in the form of two surds, where ๐ด and ๐ต are one or both quadratic surds and ๐‘› is odd. Take ๐‘ž such that ๐‘ž(๐ด2โˆ’๐ต2) may be a perfect ๐‘›th power, say ๐‘๐‘›. Take ๐‘  and ๐‘ก the nearest integers to ๐‘›๐‘ž(๐ด+๐ต)2 and ๐‘›๐‘ž(๐ดโˆ’๐ต)2, then ๐‘›๐ด+๐ต=12 2๐‘›๐‘ž{๐‘ +๐‘ก+2๐‘ยฑ๐‘ +๐‘กโˆ’2๐‘}

Examples

To reduce 5893+1092 Here ๐ด=893, ๐ต=1092 ๐ด2โˆ’๐ต2=1; โˆด ๐‘=1 and ๐‘ž=1. 5๐‘ž(๐ด+๐ต)2=9+๐‘“5๐‘ž(๐ดโˆ’๐ต)2=1โˆ’๐‘“}, ๐‘“ being a proper fractio; โˆด ๐‘ =9, ๐‘ก=1. Result, 12(9+1+2ยฑ9+1โˆ’2)=3+2

Sources and References

https://archive.org/details/synopsis-of-elementary-results-in-pure-and-applied-mathematics-pdfdrive

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ID: 210600009 Last Updated: 6/9/2021 Revision: 0 Ref:

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References

  1. B. Joseph, 1978, University Mathematics: A Textbook for Students of Science &amp; Engineering
  2. Wheatstone, C., 1854, On the Formation of Powers from Arithmetical Progressions
  3. Stroud, K.A., 2001, Engineering Mathematics
  4. Coolidge, J.L., 1949, The Story of The Binomial Theorem
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