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ContentTheory of Equation
Theory of EquationCubic Equations483 To solve the general cubic equation ๐ฅ3+๐๐ฅ2+๐๐ฅ+๐=0 Remove the term ๐๐ฅ2 by the method of (429). Let the transformed equation be ๐ฅ3+๐๐ฅ+๐=0 484 Cardan's method: The complete theoretical solution of this equation by Cardan's method is as follows:- Put ๐ฅ=๐ฆ+๐งi. ๐ฆ3+๐ง3+(3๐ฆ๐ง+๐)(๐ฆ+๐ง)+๐=0 Put 3๐ฆ๐ง+๐=0; โด๐ฆ=โ๐3๐งSubstitute this value of ๐ฆ, and solve the resulting quadratic in ๐ฆ3. The roots are equal to ๐ฆ3 and ๐ง3 respectively; and we have, by [i] 485 ๐ฅ= ๐2+ 13+ ๐2โ 13The cubic must have one real root at least, by (409). Let ๐ be one of the three values of ๐2+ 13, and ๐ one of the three values ๐2โ 13. 486 Let 1, ๐ผ, ๐ผ2 be the three cube roots of unity, so that ๐ผ=โ 12+ 12 12โ 12 ๐2ยฑ 13by the Binomial Theorem, we put ๐= the sum of the odd terms, and ๐= the sum of the even terms then we shall have ๐=๐+๐, and ๐=๐โ๐; or else ๐=๐+๐ Assume ๐ฅ=๐ ๐๐2 ๐๐3=0 But 34 =0By (657) Equate coefficients in the two equations; the result is ๐= 4๐3 12, 34๐ 12๐ผ must now be found with the aid of the Trigonometrical tables. 490 The roots of the cubic will be ๐ 23๐+๐ผ), ๐ 23๐โ๐ผ) 491 Observe that, according as ๐24+๐327 is positive or negative, Cardan's method or the Trigonometrical will be practicable. In the former case, there will be one real and two imaginary roots; in the latter case, three real roots. Sources and Referenceshttps://archive.org/details/synopsis-of-elementary-results-in-pure-and-applied-mathematics-pdfdriveยฉsideway ID: 210800012 Last Updated: 8/12/2021 Revision: 0 Ref: References
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