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Algebra
 Simultaneous Equations
  General Solution with Two Unknown Quantities
  General Solution with Three Unknown Quantities
 Methods of Solving simultaneous Equations between Two Unknown Quantities
  By substitution
   Examples
  By the Method of Multipliers
   Examples
  By changing the quantities sought
   Examples
   Examples
  By Substituting 𝑦=𝑡𝑥
   Examples
   Examples
 Sources and References

Algebra

Simultaneous Equations

General Solution with Two Unknown Quantities

Given 𝑎1𝑥+𝑏1𝑦=𝑐1𝑎2𝑥+𝑏2𝑦=𝑐2}, 𝑥=𝑐1𝑏2−𝑐2𝑏1𝑎1𝑏2−𝑎2𝑏1 𝑦=𝑐1𝑎2−𝑐2𝑎1𝑏1𝑎2−𝑏2𝑎1

General Solution with Three Unknown Quantities

Given 𝑎1𝑥+𝑏1𝑦+𝑐1𝑧=𝑑1𝑎2𝑥+𝑏2𝑦+𝑐2𝑧=𝑑2𝑎3𝑥+𝑏3𝑦+𝑐3𝑧=𝑑3}, 𝑥=𝑑1(𝑏2𝑐3−𝑏3𝑐2)+𝑑2(𝑏3𝑐1−𝑏1𝑐3)+𝑑3(𝑏1𝑐2−𝑏2𝑐1)𝑎1(𝑏2𝑐3−𝑏3𝑐2)+𝑎2(𝑏3𝑐1−𝑏1𝑐3)+𝑎3(𝑏1𝑐2−𝑏2𝑐1) and symmetrical forms for 𝑦 and 𝑧.

Methods of Solving simultaneous Equations between Two Unknown Quantities

By substitution

Find one unknown in terms of the other from one of the two equations, and substitute this value in the remaining equation. Then solve the resulting equation.

Examples

𝑥+𝑦=237𝑦=28} From (2), 𝑦=4, substitute in (1); thus 𝑥+20=23, 𝑥=3

By the Method of Multipliers

Examples

3𝑥+5𝑦=362𝑥−3𝑦=5} Eliminate 𝑥 by multiplying (1) by 2 and (2) by 3; thus 6𝑥+10𝑦=726𝑥−9𝑦=15} By subtraction 19𝑦=57 𝑦=3 By substitution in (2) 𝑥=7

By changing the quantities sought

𝑥−𝑦=2𝑥2−𝑦2+𝑥+𝑦=30} Let 𝑥+𝑦=𝑢, 𝑥−𝑦=𝑣, and substitute in equations: 𝑣=2𝑢𝑣+𝑢=30} ∴ 2𝑢+𝑢=30 𝑢=10 ∴ 𝑥+𝑦=10 𝑥−𝑦=2 From which 𝑥=6, and 𝑦=4

Examples

2𝑥+𝑦𝑥−𝑦+10𝑥−𝑦𝑥+𝑦=9𝑥2+7𝑦2=64} Substitute 𝑧 for 𝑥+𝑦𝑥−𝑦 in (1): ∴ 2𝑧+10𝑧=9 2𝑧2−9𝑧+10=0 From which 𝑧=52 or 2, 𝑥+𝑦𝑥−𝑦=2 or 52. From which 𝑥=3𝑦 or 73𝑦 Substitute in (2), thus 𝑦=2 and 𝑥=6, or 𝑦=67 and 𝑥=27

Examples

3𝑥+5𝑦=𝑥𝑦2𝑥+7𝑦=3𝑥𝑦} Divide each quantity by 𝑥𝑦 3𝑦+5𝑥=12𝑦+7𝑥=3} Multiply (3) by 2, and (1) by 3, and by subtraction 𝑦 is eliminated.

By Substituting 𝑦=𝑡𝑥

By Substituting 𝑦=𝑡𝑥, when the equations are homogeneous in the terms which contain 𝑥 and 𝑦.

Examples

52𝑥2+7𝑥𝑦=5𝑦215𝑥−3𝑦=172} From (1) and (2), 52𝑥2+7𝑡𝑥2=5𝑡2𝑥235𝑥−3𝑡𝑥=174} (3) gives 52+7𝑡=5𝑡2 A quadratic equation from which 𝑡 must be found, and its value substituted in (4). 𝑥 is thus determined; and then 𝑦 from 𝑦=𝑡𝑥.

Examples

2𝑥2+𝑥𝑦+3𝑦2=1613𝑦−2𝑥=42} From (1) and (2), by putting 𝑦=𝑡𝑥, 𝑥2(2+𝑡+3𝑡2=163𝑥(3𝑡−2)=44} Squaring (4), 𝑥2(9𝑡2−12𝑡+4)=16 ∴ 9𝑡2−12𝑡+4=2+𝑡+3𝑡2, a quadratic equation for 𝑡. 𝑡 being found from this, equation (4) will determine 𝑥; and finally 𝑦=𝑡𝑥.

Sources and References

https://archive.org/details/synopsis-of-elementary-results-in-pure-and-applied-mathematics-pdfdrive

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ID: 210600003 Last Updated: 6/3/2021 Revision: 0 Ref:

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References

  1. B. Joseph, 1978, University Mathematics: A Textbook for Students of Science & Engineering
  2. Wheatstone, C., 1854, On the Formation of Powers from Arithmetical Progressions
  3. Stroud, K.A., 2001, Engineering Mathematics
  4. Coolidge, J.L., 1949, The Story of The Binomial Theorem
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