 output.to from Sideway
Mechanics: Statics

Draft for Information Only

# Content

``` Simple Planar Truss  Stability: Determinacy: Forces Analysis by Method of Joints:```

# Simple Planar Truss

## Stability:

In truss design, one of the main concern is the stability of the structure. Because truss members are assumed to be connected by frictionless pin, the bending moment between members is negligible and truss members can rotate freely about the joint. Besides the need of proper constraints to maintain the stability of a truss, any unstable arrangement of members should also be eliminated. For example, the top storey is unstable and the truss will colllapse when appling force Q. If a simple truss is made of four members connected by pins, the truss will be easily deformed by appling a load at its upper corner. However, If the member of a simple truss is made of three members connected by pins, the truss will be deformed slightly only when appling a load at its upper corner. The geometrical shape of the truss remains unchange under loading, the only possible deformation is the dimensional changes in the length of the truss member due to the applied load. This type of truss is so called rigid truss because the truss will not collapse under loading. The truss does not collapse because the motion of connection pin joint is interlocked by fixing the other ends of the two connected truss members. By applying similar strategy, a larger rigid truss can be built by adding two truss members to the existing joints of the basic simple truss and the other ends are then connected by a frictionless pin to form a new joint which should not lie beween the two joining joints in the form of a straight line. In general, new members are usually joined to the neighborhood joints belong to the same truss member to form a new triangle of the truss. However, they can also be attached to two seperated joints belong to two different truss members. Although the four truss members usually form a triangle, sometimes they are not. In general, a rigid truss can be constructed by starting with a basic triangular truss with three members and three joints. Therefore, for constructing a rigid truss, two more members and one more joint are added to the rigid truss. Mathematically, the total number of member m is equal to 2 times the total number of joints minus 3, i.e. m=2n-3. In other words,  the structure of a simple rigid truss alway have the equation equal to m=2n-3.

## Determinacy:

Since all truss members are two force member, each member has only one unknown force. The total number of unknown force is equal to the total number of truss member, M. Assume the total number of  unknown reactions in a two dimensional structure is R. Therefore the number of unknowns for a constrained truss is equal to number of truss members, M plus number of reactions, R, i.e.  total number of unknowns = M+R.

At each joint, there is no couple and two equilibrium equations of rectangular componenets can be formulated only. Therefore the number of equilibrium equations for a truss with number of joint N is 2 times the number of joints. i.e. total number of equilibrium equations = 2 N.

Although there are three more equilibrium equations can be written from the free body diagram of truss since the truss is in static equilibrium, these three equilibrium equations are not independent equation. These static equilibrium equations can only provide additional relationship between external forces.

A truss is statically determinate, only when the number of unknowns is equal to the number of equilibrium equations, i.e. M+R=2N. For a two dimensional completely constrained structure, the total number of reactions, R is equal to 3. The equation can be rewritten as M+3=2N or M=2N-3, which is same as the stability requirement, m=2n-3. Therefore a stable truss is statically determinate only if the truss is properly constructured.

When an additional member is added to a stable truss, the truss becomes over rigid and is statically indeterminate. For example. additional diagonal of a "X" crossed panel in a truss. ## Forces Analysis by Method of Joints:

The method of joints is a general method used to calculate forces in trusses. Since all forces passes through the truss joints, there is no couple at the truss joints and moment equilibrium equation is not necessary to be considered in the force analysis at joint. However moment equilibrium equation still can be used on the static analysis of a truss. For example, a simple truss bridge with concentrated load P. The free body diagram of the truss bridge is After setting up the three equilibrium equations for the truss structure, all reactions can be determined accordingly. In order to analyze the members in truss, corresponding free body diagrams of joints and members are constructed by dis-assembly the truss structure into component parts, imply For a two force member, the force in the truss member is either tensile or compressive force only. Since all forces are acting on truss joint pins only, the two forces at the two end joints of a truss member should be equal in magnitude and line of action but opposite in sense when the truss is in equilibrium. The force in the member can be assumed either tensile or compressive, the sense of the direction will confirm whether the assumption is correct or not.

And by Newton's third law, the action and reaction forces between a joint pin and a truss member are always equal and opposite. Therefore at each joint, every connected truss member will exert an force of equal in magnitude and line of action, and opposite in sense on the joint pin. Since the truss is in equilibrium, the resultant force of all forces including truss reactions, applying loads and reactions acting on the joint pin is equal to zero.

Assuming all positive vectors in scalar, the two equilibruim equations on each joint is By making use of the truss trigonometry, eight unknowns can then be expressed into eight force equilibrium equations, imply ©sideway References

1. I.C. Jong; B.G. rogers, 1991, Engineering Mechanics: Statics and Dynamics, Saunders College Publishing, United States of America
2. F.P. Beer; E.R. Johnston,Jr.; E.R. Eisenberg, 2004, Vector Mechanics for Engineers: Statics, McGraw-Hill Companies, Inc., New York ID: 120200071 Last Updated: 2016/3/8 Revision: 1 Ref: Home (5)

Business

Management

HBR (3)

Information

Recreation

Hobbies (7)

Culture

Chinese (1097)

English (336)

Reference (66)

Computer

Hardware (149)

Software

Application (187)

Digitization (24)

Numeric (19)

Programming

Web (648) CSS (SC)

ASP.NET (SC)

HTML

Knowledge Base

Common Color (SC)

Html 401 Special (SC)

OS (389)

MS Windows

Windows10 (SC)

.NET Framework (SC)

DeskTop (7)

Knowledge

Mathematics

Formulas (8)

Number Theory (206)

Algebra (20)

Trigonometry (18)

Geometry (18)

Calculus (67)

Complex Analysis (21)

Engineering

Tables (8)

Mechanical

Mechanics (1)

Rigid Bodies

Statics (92)

Dynamics (37)

Fluid (5)

Control

Acoustics (19)

Biology (1)

Geography (1)

Copyright © 2000-2019 Sideway . All rights reserved Disclaimers last modified on 10 Feb 2019